Arshdeep Singh celebrates wicket with unique dance step in ODI

Yahoo Sports • 1 min read • Latest: Nov 4, 2026, 7:00 AM

Last updated Nov 4, 2026

Arshdeep Singh celebrates wicket with unique dance step in ODI
Summary

Arshdeep Singh took 4 wickets for 70 runs, leading India in the first ODI against New Zealand in Auckland on November 4. After dismissing Kyle Jamieson, he performed a dance step celebration inspired by his girlfriend. The celebration sparked social media discussions, with Arshdeep explaining it was intended to lift each other's spirits. He became only the second Indian pacer to achieve a four-wicket haul in ODIs at Eden Park, following Javagal Srinath. As Arshdeep expressed his enjoyment of bowling in favorable conditions, the match continues with New Zealand facing pressure at 131 for 8.

Source Links
By the Numbers
  • •Arshdeep Singh recorded 4/70 in the first ODI against New Zealand.
  • •He dismissed Will Young, Henry Nicholls, Jamieson, and Glenn Phillips.
  • •The unique celebration is a dance step shared with his girlfriend.
  • •India leads in the match with New Zealand at 131 for 8.
  • •This performance marks Arshdeep's place in ODI history at Auckland.
Latest Updates
  • 7:00 AMYahoo Sports — Explained: Arshdeep Singh 'steps celebration' after dismissing Kyle Jamieson in 1st ODI in Auckland
What they're saying
"

Wondering why Arshdeep Singh celebrated with a unique dance step after dismissing Kyle Jamieson in Auckland? Here is what the Indian pacer revealed.

Related Teams & Leagues

Sources

External links

Original reporting and copyright belong to the linked sources. SportsNewsReport.com aggregates and links — it does not republish full articles.

Related Stories

Last 14 days