Yoshinobu Yamamoto strikes out seven in Dodgers' win over Reds
Yahoo Sports • 1 min read • Latest: Sep 16, 2026, 3:24 AM
Last updated Sep 16, 2026
Yoshinobu Yamamoto pitched seven scoreless innings for the Dodgers in Cincinnati, striking out seven and allowing just one hit in a 4-0 victory. Despite walking the first two batters he faced, Yamamoto settled down to retire the final 13 hitters. Manager Dave Roberts praised his ability to make adjustments during the game. As the playoffs approach, Yamamoto continues to demonstrate consistency amid a competitive pitching in the National League.
- •Yamamoto walked the first two batters on four pitches each.
- •He struck out seven and allowed one hit overall.
- •The Dodgers improved their standing with the 4-0 victory.
- •Yamamoto's adjustments were key after a shaky start.
- •The game took place on September 15, 2026.
- 3:24 AMYahoo Sports — Yoshinobu Yamamoto's 4-pitch leadoff walk was a red flag. The Dodgers' ace proved it was a fluke
"Yamamoto has carried metronomical energy this season. And with October just around the corner, the 2025 World Series hero is looking primed to carry the torch for the Dodgers again.
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