Yoshinobu Yamamoto loses perfect game on Mookie Betts error in eighth
Yahoo Sports • 1 min read • Latest: Jun 13, 2026, 10:53 PM
Last updated Jun 13, 2026
Yoshinobu Yamamoto narrowly missed his first MLB no-hitter and a perfect game during the Dodgers' matchup against the White Sox on June 13, 2026. The right-hander lost a perfect game in the eighth inning when shortstop Mookie Betts committed an error. Yamamoto's no-hit bid ended shortly after in the ninth when Tristan Peters hit a home run, though he managed to finish the game with a strong overall performance. The Dodgers secured a 7-1 victory in the game, which followed a disappointing 8-2 loss the previous day. The outing reaffirmed Yamamoto’s impressive season and showcased Shohei Ohtani's return from injury with a homer in this game.
- •Yamamoto allowed one hit and one error in the game.
- •He retired 45 consecutive batters prior to the Betts error.
- •Tristan Peters’ home run ended both the no-hitter and the shutout.
- •The Dodgers improved to 7-1 with this victory over the White Sox.
- •Shohei Ohtani returned with a home run and contributed two runs.
- 10:53 PMYahoo Sports — Dodgers star Yoshinobu Yamamoto loses perfect game on Mookie Betts error in 8th inning, then loses no-hitter in 9th
"Sandy Koufax remains the only Dodger to throw a perfect game.
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